python中filter|map函数传入多个参数的方法

借助lambda

• filter

def foo(a, b, c):
    return a < b and b < c

myTuple = (1, 2, 3, 4, 5, 6)

# 找到大于1，小于4的值
print(list(filter(lambda x: foo(1, x, 4), myTuple)))
# (2, 3)

• map

def func(x, y):
    print(x, y)
    return x + y

a = [1, 2]
data = list(map(lambda x: func(x, 88), a))
print(data)
# 1 88
# 2 8
# [89, 90]